-24x^2-28x+12=0

Solution for -24x^2-28x+12=0 equation:

-24x^2-28x+12=0

a = -24; b = -28; c = +12;
Δ = b2-4ac
Δ = -282-4·(-24)·12
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-44}{2*-24}=\frac{-16}{-48}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+44}{2*-24}=\frac{72}{-48}
=-1+1/2
$